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Pl0x

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Forum » Off Topic » Pl0x 11 posts - page 1 of 2
Permalink | Quote | +Rep by TormentedTurnip » September 25, 2013 11:22am | Report
Just posted this on another community site that I frequent, but I feel like that place is dying so I'm gonna go ahead and repeat it here:



I feel like I have misplaced a parenthesis or done something incorrectly somewhere in this...thing.


y=cot5(sec2(6x3+5x)4), which is equivalent to (cot(sec(6x3+5x)4)2)5

So,

y'= 5(cot(sec(6x3+5x)4)2)4 · -csc2(sec2(6x3+5x)4)2 · 2(sec(6x3+5x)4) · (sec2(6x3+5x)4)(tan(6x3+5x)4) · 4(6x3+5x)3 · 18x2 +5.


If you want to plug in a value for "x" and actually solve it, be my guest...LOL, but yeah if you spot any errors in deriving it please let me know.

Edit: fixed one and had a funky "Ã" going on in there, lol.
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Permalink | Quote | +Rep by JararoNatsu » September 25, 2013 5:59pm | Report
I have a friend who is a calculus junkie. If I see him later tonight, I will have him look at this for you.

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Permalink | Quote | +Rep by TormentedTurnip » September 25, 2013 6:13pm | Report
Thanks, a helpful person on my other site said that I actually can't use that method when trigonometry terms are in there, so it might all be wrong. If that's the case: ****.

lol

I'll wait to see what your friend says, too. It's not something I need graded, but something I just want to get correct.
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Permalink | Quote | +Rep by M4XiiMUS » September 25, 2013 6:40pm | Report
So wait.. Why do you want this solved?
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Permalink | Quote | +Rep by TormentedTurnip » September 25, 2013 6:47pm | Report
It was a problem given in class that was never properly solved and it's bugging me.
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Permalink | Quote | +Rep by M4XiiMUS » September 25, 2013 7:36pm | Report
Oh.
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Permalink | Quote | +Rep by JararoNatsu » September 25, 2013 9:43pm | Report
Well, he is busting out the Juggernaut (super awesome calculator). Courtesy of SnubMachina:

It's a very difficult problem. You were on the right track. As for your derivative of Sec(" ") remember it's that (d/dx)sec(x) = sec(x)tan(x) not (sec(x))^2 tan(x). As for the entire problem I can't help too much because I don't want to give you the wrong answer (or type that **** out), but you have the right idea. Go to wolfram and see what it tells you, that's probably your best resource.

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Permalink | Quote | +Rep by RazeMage » September 25, 2013 10:23pm | Report
....., i don't want to finish school now .-.
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Permalink | Quote | +Rep by TormentedTurnip » September 26, 2013 5:15am | Report
Tell your friend thanks! Don't know why I thought sec2(x)tan(x) was the derivative, I must've had an inkblot over it.

Okay, if everything seems right I will actually attempt to solve it and see what my professor says tomorrow. I just didn't want to walk in there with something way off, xD
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Permalink | Quote | +Rep by TormentedTurnip » September 26, 2013 5:17am | Report
RazeMage wrote:

....., i don't want to finish school now .-.

Don't worry, it's not even something required in the curriculum, and certainly not going to be even mentioned in high school. Finish your education, boy!
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