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TormentedTurnip's Blog
Blog Posts: 24     Views: 48841     Comments: 177
TormentedTurnip
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November 18, 2014

Math Wat R U Doin

Views: 1704 TormentedTurnip
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Well it's 3:30 am and it looks like I'm not going to be able to finish part 4C but I'm too tired to care anymore >.<

There's probably errors in here but I think the proofs are pretty solid, thought I'd share.


















Aaand, the one I couldn't finish. I've got about eight pages of scratch work but I just can't crack this damn puzzle >.< and I bet it's so simple once you know it too, /sigh






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November 17, 2014
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FUCK
I just stocked up on groceries two days ago and my power went out. Thr fridge idn't running guises HALP

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September 29, 2014

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April 29, 2014

One Spot Stop for All Your Coding Needs!

Views: 1711 TormentedTurnip
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in  |  Jojobanito
Instead of having two separate guides for different aspects of BBCoding, our dear Jojobanito and I have decided to merge our coding guides into one. Check it out on Jordenito's profile page!

I won't be taking my desktop with me when I transfer colleges this fall, so Jojobanito is the one who'll be keeping it up-to-date with new templates/coding innovations that will hopefully be provided to him by the ever increasing community here.

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March 26, 2014

Another Math Problem :D

Views: 2709 TormentedTurnip
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oh lawdy
Well, I can't help sharing what I learn. I'm finally able to focus specifically on the courses in my major, and I'm really enjoying it.


This is a problem solved using the Partial Fraction Decomposition method:






Basically, you have to factor the denominator, and then set the equivalent expression equal to multiple fractions (however many you need in order to not have any products in the denominators). You basically just set the actual integral to the side for the next few steps, which is just setting the variable x (well, in this example, at least) equal to numbers that eliminate all but one unknown. After repeating the process until you have solved every unknown, you can head back to the original integral, setting it equal to the new expression. From there, you simply find the anti-derivatives of each piece and you're done! :D

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